May 11 2020

1W Audio amp, max. voltage 12V, Case DIP8Datasheet. Texas Instruments. Part No. 74LVC1GDBVRG4. Description, LVC/LCX/Z SERIES, 3-INPUT XOR GATE, PDSO6, GREEN, PLASTIC, SOT, 6 PIN. The LM is an integrated circuit containing a low voltage audio power amplifier . It is suitable are also available in a single-in-line package. JRC devices, marked as JRC, are sometimes misleadingly referred to as the JRC

Author: Dosida Kagalabar
Country: Bahamas
Language: English (Spanish)
Genre: Finance
Published (Last): 14 December 2014
Pages: 466
PDF File Size: 15.62 Mb
ePub File Size: 18.37 Mb
ISBN: 854-8-66354-912-4
Downloads: 90901
Price: Free* [*Free Regsitration Required]
Uploader: Grozragore

DigiKey carries the LM in two voltage flavors.

Would you believe me if I told you I’m a millionaire? This will be the test circuit on the breadboard.

China Jrc d, China Jrc d Manufacturers and Suppliers on

Hi, this is Helectronics. I made a drawing about the circuit so it is more simple to understand it. I highly recommend to make a test on a breadboard before making a PCB, so you’ll be sure it will work perfectly. Then when it doesn’t work, you will know it’s not because of hrc chip substitution. These PCB connectors are very useful, you can connect this circuit anywhere easily. I put a link in the description for the picture.

Low Voltage Audio Mono Amp IC Njm386d JRC 386d X4pcs

Activity Activity Annotations Notes Edits. Edit, answering your Additional Details: Other outfits carry the SIP version, too: A microfarad capacitor is also placed, these two capacitors will stabilize the supply voltage so the amp will work without noise. Are you sure you want to delete this answer? Chat or rant, adult content, spam, insulting other members, show more. It is also important to make the leads short and the components should be close to each other, so it won’t pick up any noise.


Answer Questions Electrical network question to find current please help? In my homemade boombox in which I will use this preamplifier, the supply voltage is 18 volts so I will have to use a 9 volt regulator in order to operate this IC.

Another picofarad capacitor is placed between the pin 2 and pin 4 or the ground. How do you integrate a 9v DC circuit into a device that already has a v AC power coming in to it?

I think the final result 38d very good, it looks nice and also sounds great.

If you use this circuit as a preamplifier, then these two components must be left out. Now, I place a jumper wire from the pin 4 to the ground rail. How can i calculate the ratios of a gear train correctly?


A 10 microfarad capacitor is placed between the pin 7 and pin 4, the negative side 386e the capacitor goes to the pin 4. Do Intergrated Circuit housings have to face a certain way? Resource for Civil Engineering news? These two components form a low-pass filter.

Harm to minors, violence or threats, harassment or privacy invasion, impersonation or misrepresentation, fraud or phishing, show more. Here are some features of this IC.

Thank you for watching, leave a like if you want to see more videos like this.

Permalink Edit Editors Share Share 38d annotation: This green wire will be the output, it is connected to the negative terminal of the microfarad capacitor. This integrated circuit is commonly used in small radios and DIY guitar preamp circuits, because it can also 386v with just a 9 volt battery. These are the electrical characteristics. I would choose the V version since the rambler is powered from a 9V source.


Electrical circuit find current pls help? The yellow wire goes to the non-inverting input. A resistor with the value of ohm is connected to the capacitor which is also connected to the ground pin.

The end of the triangular plate are subjected to three couples. A 15 ohm resistor is placed also to the output along with the picofarad capacitor, which is connected to the ground. After placing the 386e, I put the voltage regulator on the board.

50x LOT D JRC Audio Amplifier Low Voltage Mono AMP IC NJMD US SHIP! | eBay

Stuck Circuit Breaker Switch? Make sure that the positive side is connected to the resistor and the capacitor. This IC is designed jgc for battery usage, as you can see the quiescent current is very low, but this time for me it is not so important. This capacitor also helps to eliminate noise.

I place a jumperwire from the voltage regulator’s third pin, to the IC’s sixth pin. The black wire is connected to the ground rail. Have a good day! Electrical network question to find current please help? The blue wire goes to the pin 2, or the inverting input.